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Question: A body is projected at 30<sup>0</sup>angle with the horizontal with velocity 30 ms<sup>–1</sup>. Wha...

A body is projected at 300angle with the horizontal with velocity 30 ms–1. What is the angle with the horizontal after 1.5 s ? (Take g = 10 m s–2)

A

00

B

300

C

600

D

900

Answer

00

Explanation

Solution

Time to reach at maximum height

t = usinθg\frac { u \sin \theta } { g } = 30sin3010\frac { 30 \sin 30 ^ { \circ } } { 10 } = 1.5

So, particle at maximum height.