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Physics Question on Motion in a plane

A body is moving with velocity 30 ms30\, ms towards east After 10 s its velocity becomes 40 ms40 \,ms towards north. The average acceleration of the body is

A

7 ms−17\, ms^{-1}

B

7 ms−1\sqrt{7}\,ms^{-1}

C

5 ms−15\,ms^{-1}

D

1 ms−21 \,ms^{-2}

Answer

5 ms−15\,ms^{-1}

Explanation

Solution

Average acceleration
A⃗avg =v⃗f−v⃗it=40 j^−30 i^10\vec{ A }_{\text {avg }}=\frac{\vec{ v }_{ f }-\vec{ v }_{ i }}{ t }=\frac{40 \,\hat{ j }-30 \,\hat{ i }}{10}
A⃗avg =402+30210=5 m/ sec2\vec{ A }_{\text {avg }}=\frac{\sqrt{40^{2}+30^{2}}}{10}=5 \,m / \,sec ^{2}