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Question: A body is moving with uniform speed v on a horizontal circle from A as shown in the fig. Change in v...

A body is moving with uniform speed v on a horizontal circle from A as shown in the fig. Change in velocity in the first quarter revolution is

A

v2

B

√2 v southwest

C

√2 north west

D

2v west

Answer

√2 v southwest

Explanation

Solution

For quarter revolution

Δv=v2(i^)v1j^\Delta\overrightarrow{v} = v_{2}\left( - \widehat{i} \right) - v_{1}\widehat{j}

or Δv=vi^vj^\Delta\overrightarrow{v} = - v\widehat{i} - v\widehat{j}

∴ ∆v = v2+v2\sqrt{v^{2} + v^{2}} = 2v\sqrt{2}v

Also α = tan-1vv=45o\frac{v}{v} = 45^{o}

Δv=2v\Delta\overrightarrow{v} = \sqrt{2}v south west.