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Question: A body is moving with uniform acceleration describes 40 m in the first 5 sec and 65 m in next 5 sec....

A body is moving with uniform acceleration describes 40 m in the first 5 sec and 65 m in next 5 sec. Its initial velocity will be

A

4 m/s

B

2.5 m/s

C

5.5 m/s

D

11 m/s

Answer

5.5 m/s

Explanation

Solution

S1=ut+12at2\because S_{1} = ut + \frac{1}{2}at^{2} .....(i)

and velocity after first t sec

v=u+atv = u + at

Now, S2=vt+12at2S_{2} = vt + \frac{1}{2}at^{2}

=(u+at)t+12at2= (u + at)t + \frac{1}{2}at^{2} ..... (ii)

Equation

S2S1=at2\Rightarrow S_{2} - S_{1} = at^{2}

a=S2S1t2=6540(5)2=16mum/s2\Rightarrow a = \frac{S_{2} - S_{1}}{t^{2}} = \frac{65 - 40}{(5)^{2}} = 1\mspace{6mu} m/s^{2}

From equation (i), we get,

S1=ut+12at240=5u+12×1×25S_{1} = ut + \frac{1}{2}at^{2} \Rightarrow 40 = 5u + \frac{1}{2} \times 1 \times 25

5u=27.5\Rightarrow 5u = 27.5 6mu6muu=5.56mum/s\therefore\mspace{6mu}\mspace{6mu} u = 5.5\mspace{6mu} m/s