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Question: A body is moving with a variable acceleration (a) along a straight line. The average acceleration of...

A body is moving with a variable acceleration (a) along a straight line. The average acceleration of the body in time interval t1{t_1} to t2{t_2} is

Explanation

Solution

Total acceleration is what we are looking for in this question. Also during a straight-line motion, velocity and acceleration do not depend on the direction vector of the path as the direction can arbitrarily be assumed to be the +X axis.

Formulas used:
The average acceleration is the definite integral of instantaneous acceleration between the given limits of the time period divided by the total time divided by the total time of travel.
aavg=t1t2adttnet{a_{avg}} = \dfrac{{\int\limits_{{t_1}}^{_{{t_2}}} {adt} }}{{{t_{net}}}} where anet{a_{net}} is the net acceleration, a is the instantaneous acceleration and t1{t_1} to t2{t_2} is the time interval and tnet{t_{net}} is the total time taken for travel.
Total time is nothing but the difference t1{t_1} and t2{t_2} .
tnet=t2t1{t_{net}} = {t_2} - {t_1}

Complete step by step answer:
Here in this question, the acceleration is variable which means that it is changing with every interval of time. As such we need to calculate the sum of acceleration for all those intervals of time after breaking up the total travel duration into countless small parts. This can be done by integration. Also, the travel occurs in a limited time interval which is from t1{t_1} to t2{t_2} . As such the limits of integration will be t1{t_1} and t2{t_2} . As such the average acceleration is given by
aavg=t1t2adttnet{a_{avg}} = \dfrac{{\int\limits_{{t_1}}^{_{{t_2}}} {adt} }}{{{t_{net}}}}
where anet{a_{net}} is the net acceleration, a is the instantaneous acceleration and t1{t_1} to t2{t_2} is the time interval and tnet{t_{net}} is the total time taken for travel.
Time taken for this trip is the total time which is nothing but the t1{t_1} and t2{t_2} . It is given by
tnet=t2t1{t_{net}} = {t_2} - {t_1}
As such the average acceleration will be
aavg=t1t2adtt2t1{a_{avg}} = \dfrac{{\int\limits_{{t_1}}^{_{{t_2}}} {adt} }}{{{t_2} - {t_1}}}

Note: Here students make the error of calculating the average acceleration by just integrating the instantaneous acceleration with respect to time but that is not average acceleration rather it is a jerk.