Question
Question: A body is moving with a speed of \( 1m/s \) and a constant force \( F \) is needed to stop it in a d...
A body is moving with a speed of 1m/s and a constant force F is needed to stop it in a distance x . If the speed of the body is 3m/s the force needed to stop it in the same distance x will be :
(A) 1.5F
(B) 3F
(C) 6F
(D) 9F
Solution
Here in this question we have to find the force required to stop and from this, we will use the equation v2=u2+2as . From this, we will get the ratio of the acceleration and by equating the acceleration we will get to the answer.
Formula used
v2=u2+2as
Here, v , will be the final velocity,
u , will be the initial velocity,
s , will be the displacement.
Complete step by step answer:
So in this question, we have the initial velocity given and in each of the cases the final velocity will be zero. So by using the formula for the first case the equation will become
⇒v2=u2+2a1s
And on substituting the values. We will get the equation as
⇒02=32+2a1x
And on taking the constant term one side, we get
⇒a1=2x32
And on solving the above equation, we get
⇒a1=2x9
Similarly, for the first case, the equation will become
⇒v2=u2+2a2s
And on substituting the values. We will get the equation as
⇒02=12+2a2x
And on taking the constant term one side, we get
⇒a2=2x12
And on solving the above equation, we get
⇒a2=2x1
So on equating bot the acceleration, we will get the equation as
⇒9a1⋅2x=1a2⋅2x
Since the like term will cancel each other, so we get
⇒a1=9a2
Here, the mass will be constant.
Therefore, the required force will be nine times greater than the earlier force.
Hence, the option (D) is correct.
Note:
For solving such types of questions we have to play with the equations and for this, the concept should be clear. And also we have to first check the units whether it is correct or needed to be changed then only we should proceed further for solving it.