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Question: A body is moving under the action of two forces\({\overrightarrow{F}}_{1} = 2\widehat{i} - 5\widehat...

A body is moving under the action of two forcesF1=2i^5j^;F2=3i^4j^{\overrightarrow{F}}_{1} = 2\widehat{i} - 5\widehat{j};{\overrightarrow{F}}_{2} = 3\widehat{i} - 4\widehat{j}. Its velocity will become uniform under a third force F3{\overrightarrow{F}}_{3}given by :

A

5i^j^5\widehat{i} - \widehat{j}

B

5i^j^- 5\widehat{i} - \widehat{j}

C

5i^+j^5\widehat{i} + \widehat{j}

D

5i^+j^- 5\widehat{i} + \widehat{j}

Answer

5i^+j^- 5\widehat{i} + \widehat{j}

Explanation

Solution

For uniform velocity, acceleration is zero. Hence resultant force will be zero

F1+F2+F3=0\therefore\overset{\rightarrow}{F_{1}} + {\overset{\rightarrow}{F}}_{2} + \overset{\rightarrow}{F_{3}} = 0

}{or\overset{\rightarrow}{F_{3}} = ( - 5\overset{\land}{i} + 9\overset{\land}{j})}$$