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Question: A body is moving under the action of two forces \( {\vec F_1} = 2\hat i - 5\hat j \) ; \( {\vec F_2}...

A body is moving under the action of two forces F1=2i^5j^{\vec F_1} = 2\hat i - 5\hat j ; F2=3i^4j^{\vec F_2} = 3\hat i - 4\hat j . Its velocity will become uniform under a third force F3{\vec F_3} given by
A. 5i^j^5\hat i - \hat j
B. 5i^j^- 5\hat i - \hat j
C. 5i^+j^5\hat i + \hat j
D. 5i^+9j^- 5\hat i + 9\hat j

Explanation

Solution

Uniform velocity- When the body covers equal distances in equal intervals of time in a particular direction it is said to be moving with a uniform velocity. There is no change in speed or direction observed in this kind of motion. Example – Movement of hands of a clock. Rotation of Earth about its axis.

Complete step by step answer:
For uniform velocity, there is no change in magnitude or direction in the motion of the body. Hence there is no acceleration. Acceleration is the rate at which velocity of a body changes with time. In the case of uniform velocity acceleration is zero.
Newton’s Second law of Motion states that rate of change of momentum of a body is directly proportional to the force applied on it.
We know,
F=maF = ma where FF is the force applied on the body, mm is the mass of the body, aa is the acceleration of the body.
If the acceleration of the body is zero, the force acting on the body also becomes zero.
Therefore, the resultant force acting on a body moving with uniform speed will be zero.
F1+F2+F3=0{\vec F_1} + {\vec F_2} + {\vec F_3} = 0
(2i^5j^)+(3i^4j^)+F3=0\Rightarrow (2\hat i - 5\hat j) + (3\hat i - 4\hat j) + {\vec F_3} = 0
F3=(23)i^+(5+4)j^=5i^+9j^\Rightarrow {F_3} = ( - 2 - 3)\hat i + (5 + 4)\hat j = - 5\hat i + 9\hat j
Option D. 5i^+9j^- 5\hat i + 9\hat j is correct.

Note:
Velocity, Acceleration and Force are vector quantities having both magnitude and direction. Vectors along the direction of the xx axis are denoted with i^\hat i and vectors along the direction of the yy axis are denoted with j^\hat j and vectors along the direction of zz are denoted with k^\hat k .