Question
Question: A body is moving under the action of two forces \( {\vec F_1} = 2\hat i - 5\hat j \) ; \( {\vec F_2}...
A body is moving under the action of two forces F1=2i^−5j^ ; F2=3i^−4j^ . Its velocity will become uniform under a third force F3 given by
A. 5i^−j^
B. −5i^−j^
C. 5i^+j^
D. −5i^+9j^
Solution
Uniform velocity- When the body covers equal distances in equal intervals of time in a particular direction it is said to be moving with a uniform velocity. There is no change in speed or direction observed in this kind of motion. Example – Movement of hands of a clock. Rotation of Earth about its axis.
Complete step by step answer:
For uniform velocity, there is no change in magnitude or direction in the motion of the body. Hence there is no acceleration. Acceleration is the rate at which velocity of a body changes with time. In the case of uniform velocity acceleration is zero.
Newton’s Second law of Motion states that rate of change of momentum of a body is directly proportional to the force applied on it.
We know,
F=ma where F is the force applied on the body, m is the mass of the body, a is the acceleration of the body.
If the acceleration of the body is zero, the force acting on the body also becomes zero.
Therefore, the resultant force acting on a body moving with uniform speed will be zero.
F1+F2+F3=0
⇒(2i^−5j^)+(3i^−4j^)+F3=0
⇒F3=(−2−3)i^+(5+4)j^=−5i^+9j^
Option D. −5i^+9j^ is correct.
Note:
Velocity, Acceleration and Force are vector quantities having both magnitude and direction. Vectors along the direction of the x axis are denoted with i^ and vectors along the direction of the y axis are denoted with j^ and vectors along the direction of z are denoted with k^ .