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Question

Physics Question on laws of motion

A body is moving under the action of two forces F1\vec{F}_{1} =2i^=2 \hat{i} 5j^;-5 \hat{j} ; F2\vec{F}_{2} =3i^=3 \hat{i} 4j^.-4 \hat{j}. Its velocity will become uniform under a third force F3\vec{F}_{3} given by

A

5i^5 \hat{i} j^-\hat{j}

B

5i^-5 \hat{i} j^-\hat{j}

C

5i^5 \hat{i} +j^+\hat{j}

D

5i^-5 \hat{i} +9j^+9 \hat{j}

Answer

5i^-5 \hat{i} +9j^+9 \hat{j}

Explanation

Solution

For uniform velocity, acceleration is zero. Hence resultant force will be zero. \therefore\quad F1\vec{F}_{1} +F2+\vec{F}_{2} +F3=0+\vec{F}_{3}=0 (2i^5j^)\left(2\hat{i}-5\hat{j}\right) +(3i^4j^)+\left(3 \hat{i}-4\hat{j}\right) +F3=0+\vec{F}_{3}=0 or F3\vec{F}_{3} =(5i^+9j^)=\left(-5\hat{i}+9 \hat{j}\right)