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Question: A body is moving is x-y plane as shown in a circular path of radius 2 m. At a certain instant when t...

A body is moving is x-y plane as shown in a circular path of radius 2 m. At a certain instant when the body is crossing the positive y-axis its acceleration is (6i^8j^)(6\widehat{i} - 8\widehat{j}) m/s2. Then its angular acceleration and angular velocity at this instant will be –

A

3k^3\widehat{k} rad/s2 and 2k^- 2\widehat{k}rad/s respectively

B

+3k^3\widehat{k}rad/s2 and +2k^+ 2\widehat{k}rad/s respectively

C

4k^4\widehat{k}rad/s2 and 3k^- \sqrt{3}\widehat{k}rad/s respectively

D

+4k^+ 4\widehat{k}rad/s2 and +3k^+ \sqrt{3}\widehat{k}rad/s respectively

Answer

3k^3\widehat{k} rad/s2 and 2k^- 2\widehat{k}rad/s respectively

Explanation

Solution

a=6i^8j^\overrightarrow{a} = 6\widehat{i} - 8\widehat{j}

\ ar = 8 and at = 6

rw2 = 8 and ra = 6