Solveeit Logo

Question

Physics Question on Kinematics

A body is moving along a straight line with initial velocity v0. Its acceleration a is constant. After t seconds, its velocity becomes v. The average velociy of the body over the given time interval is

A

vˉ=v2+v022at\bar{v}=\frac{v^2+{v_0}^2}{2at}

B

vˉ=v2+v02at\bar{v}=\frac{v^2+{v_0}^2}{at}

C

vˉ=v2v022at\bar{v}=\frac{v^2-{v_0}^2}{2at}

D

vˉ=v2v02at\bar{v}=\frac{v^2-{v_0}^2}{at}

Answer

vˉ=v2v022at\bar{v}=\frac{v^2-{v_0}^2}{2at}

Explanation

Solution

The correct answer is (C) : vˉ=v2v022at\bar{v}=\frac{v^2-{v_0}^2}{2at}.