Question
Physics Question on laws of motion
A body is moving along a rough horizontal surface with an initial velocity 6ms−1 If the body comes to rest after travelling a distance 9m, then the coefficient of sliding friction will be
A
0.4
B
0.2
C
0.6
D
0.8
Answer
0.2
Explanation
Solution
Given : u=6m/s,s=9m,v=0 From equation of motion v2=u2−2as 0=(6)2−2×a×9 18a=36 ⇒a=2m/s2 Coefficient of sliding friction is given by μ=ga =102=0.2