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Question

Physics Question on laws of motion

A body is moving along a rough horizontal surface with an initial velocity 6ms16\, ms^{-1} If the body comes to rest after travelling a distance 9m9\, m, then the coefficient of sliding friction will be

A

0.4

B

0.2

C

0.6

D

0.8

Answer

0.2

Explanation

Solution

Given : u=6m/s,s=9m,v=0u=6\, m / s,\, s=9\, m,\, v=0 From equation of motion v2=u22asv^{2} =u^{2}-2 as 0=(6)22×a×90=(6)^{2}-2 \times a \times 9 18a=3618\, a=36 a=2m/s2\Rightarrow a=2\, m / s ^{2} Coefficient of sliding friction is given by μ=ag\mu =\frac{a}{g} =210=0.2=\frac{2}{10}=0.2