Solveeit Logo
Login

Question

Question: A body is in equilibrium under the action of three coplanar forces P, Q and R as shown in the figure...

A body is in equilibrium under the action of three coplanar forces P, Q and R as shown in the figure. Select the correct statement

A

Psin⁡α=Qsin⁡β=Rsin⁡γ\frac{P}{\sin\alpha} = \frac{Q}{\sin\beta} = \frac{R}{\sin\gamma}

B

Pcos⁡α=Qcos⁡β=Rcos⁡γ\frac{P}{\cos\alpha} = \frac{Q}{\cos\beta} = \frac{R}{\cos\gamma}

C

Ptan⁡α=Qtan⁡β=Rtan⁡γ\frac{P}{\tan\alpha} = \frac{Q}{\tan\beta} = \frac{R}{\tan\gamma}

D

Psin⁡β=Qsin⁡γ=Rsin⁡α\frac{P}{\sin\beta} = \frac{Q}{\sin\gamma} = \frac{R}{\sin\alpha}

Answer

Psin⁡α=Qsin⁡β=Rsin⁡γ\frac{P}{\sin\alpha} = \frac{Q}{\sin\beta} = \frac{R}{\sin\gamma}

Explanation

Solution

According to Lami's theorem

Psin⁡α=Qsin⁡β=Rsin⁡γ\frac{P}{\sin\alpha} = \frac{Q}{\sin\beta} = \frac{R}{\sin\gamma}