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Question: A body is given \( + 1\,C\) charge. How many electrons are added or removed from the body?...

A body is given +1C + 1\,C charge. How many electrons are added or removed from the body?

Explanation

Solution

Hint
The number of electrons in the charge is determined by the formula of charge, it gives the relation between the charge, number of electrons and the charge of the electron. By using this relation, the number of electrons added or removed from the body is determined.
The formula for the charge is given by,
Q=n×e\Rightarrow Q = n \times e
Where, QQ is the charge of the body, nn is the number of the electrons in the body and ee is the charge of the one electron in that same body.

Complete step by step answer
Given that, The charge of the body is, Q=1CQ = 1\,C.
Now, the relation between the charge, number of electron and the charge of the electron is given by,
Q=n×e...................(1)\Rightarrow Q = n \times e\,...................\left( 1 \right)
By substituting the charge of the electron in the above equation (1), then the equation (1) is written as,
1=n×e\Rightarrow 1 = n \times e
The value of the charge of the electron from the physics is given by e=1.6×1019Ce = 1.6 \times {10^{ - 19}}\,C.
Substituting the charge of the electron in the above equation, then the above equation is written as,
1=n×1.6×1019\Rightarrow 1 = n \times 1.6 \times {10^{ - 19}}
By keeping the term number of electrons in one side and the other terms in other side, then the above equation is written as,
n=11.6×1019\Rightarrow n = \dfrac{1}{{1.6 \times {{10}^{ - 19}}}}
By taking the term 1019{10^{ - 19}} from the denominator to the numerator, so that the sign of the power is changed, then the above equation is written as,
n=1×10191.6\Rightarrow n = \dfrac{{1 \times {{10}^{19}}}}{{1.6}}
On dividing the terms in the above equation, then the above equation is written as,
n=0.625×1019\Rightarrow n = 0.625 \times {10^{19}}
Thus, the above equation shows the number of electrons in the body.

Note
The number of electrons does not have any unit, because it is the number. The final answer is said as, that the body has n=0.625×1019n = 0.625 \times {10^{19}} electrons. The charge of the body has the unit Coulomb and the charge of the electron also has the unit coulomb, both are divided so the units get cancelled.