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Question: A body is executing simple harmonic motion with an angular frequency 2 *rad*/*sec*. The velocity of ...

A body is executing simple harmonic motion with an angular frequency 2 rad/sec. The velocity of the body at 20 mm displacement. When the amplitude of motion is 60 mm is

A

40 mm/sec

B

60 mm/sec

C

113 mm/sec

D

120 mm/sec

Answer

113 mm/sec

Explanation

Solution

v=ωa2y2=2(60)2(20)2v = \omega\sqrt{a^{2} - y^{2}} = 2\sqrt{(60)^{2} - (20)^{2}} = 113 mm/sec