Question

A body is executing SHM. When the displacement from the mean position is 4cm and 5 cm. The values of the corresponding velocity of the body are 10 cm s^–1 and 8 cm s^–1. Then the time period of the body is –

• A. 2ps
• B. $\frac { \pi } { 2 }$s
• C. ps
• D. $\frac { 3 \pi } { 2 }$s

Answer 1

Answer: (C)

ps

Answer 2

10 = ....(1)

8 = .....(2)

$\frac { 25 } { 16 }$ =

9a² = 625 – 256

a² = $\frac { 369 } { 9 }$ = 41

from equation (i)

10 = $\omega \sqrt { 41 - 16 }$ = w × 5 or w = 2

= 2 or T = p sec