Question

A body is executing S.H.M. When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocity of the body is 10 cm/sec and 8 cm/sec. Then the time period of the body is

• A. $2\pi sec$
• B. $\pi/2$sec
• C. $\pi sec$
• D. $3\pi/2sec$

Answer 1

Answer: (C)

$\pi sec$

Answer 2

$v = \omega\sqrt{a^{2} - y^{2}}$⇒$10 = \omega\sqrt{a^{2} - (4)^{2}}$and $8 = \omega\sqrt{a^{2} - (5)^{2}}$

On solving ω = 2 ⇒ $\omega = \frac{2\pi}{T} = 2$ ⇒ $T = \pi$sec