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Question: A body is being raised to a height h from the surface of earth. What is the sign of work done by : ...

A body is being raised to a height h from the surface of earth. What is the sign of work done by :

(i) Applied force

(ii) Gravitational force?

A

Positive, Positive.

B

Positive, Negative

C

Negative, Positive

D

Negative, Negative

Answer

Positive, Negative

Explanation

Solution

Work done, W=Fd=Fdcosθ\mathrm { W } = \overrightarrow { \mathrm { F } } \cdot \overrightarrow { \mathrm { d } } = \mathrm { Fd } \cos \theta

Where θ\theta is the angle between the force and displacement d\overrightarrow { \mathrm { d } }

(i) As the body moves along the direction of applied force.

θ=00\therefore \theta = 0 ^ { 0 } , W = Fdcos 000 ^ { 0 } =Fd. It is positive,

(ii) As the body moves in a direction opposite to the gravitational force which acts vertically downwards.

θ=180\therefore \theta = 180 ^ { \circ } W = Fdcos= - Fd. It is negative.