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Question: A body is at rest under the action of three forces, two of which are \({\overrightarrow{F}}_{1} = 4\...

A body is at rest under the action of three forces, two of which are F→1=4i^,F→2=6j^,{\overrightarrow{F}}_{1} = 4\widehat{i},{\overrightarrow{F}}_{2} = 6\widehat{j}, the third force is

A

(a) 4i^+6j^4\widehat{i} + 6\widehat{j}

A

(b) 4i^−6j^4\widehat{i} - 6\widehat{j}

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(c) −4i^+6j^- 4\widehat{i} + 6\widehat{j}

A

(d) −4i^−6j^- 4\widehat{i} - 6\widehat{j}

Explanation

Solution

(d)

Sol. F1+F2+F3=0F_{1} + F_{2} + F_{3} = 0⇒ 4i^+6j^+F3=04\widehat{i} + 6\widehat{j} + F_{3} = 0

∴F→3=−4i^−6j^{\overrightarrow{F}}_{3} = - 4\widehat{i} - 6\widehat{j}