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Question: A body freely falling from the rest has a velocity ‘v’ after it falls through a height ‘h’. The dist...

A body freely falling from the rest has a velocity ‘v’ after it falls through a height ‘h’. The distance it has to fall down for its velocity to become double, is

A

2h2h

B

4h4h

C

6h6h

D

8h8h

Answer

4h4h

Explanation

Solution

Let at point A initial velocity of body is equal to zero

For path AB : v2=0+2ghv^{2} = 0 + 2gh … (i)

For path AC : (2v)2=0+2gx(2v)^{2} = 0 + 2gx4v2=2gx4v^{2} = 2gx … (ii)

Solving (i) and (ii) x=4hx = 4h