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Question

Physics Question on mechanical properties of fluid

A body floats with one-third of its volume outside water and 3/4 of its volume outside another liquid. The density of the other liquid is

A

94gcc−1\frac{9}{4}g cc^{-1}

B

40gcc−1\frac{4}{0}g cc^{-1}

C

83gcc−1\frac{8}{3} gcc^{-1}

D

38gcc−1\frac{3}{8}g cc^{-1}

Answer

83gcc−1\frac{8}{3} gcc^{-1}

Explanation

Solution

Let V be volume of the body. In water weight of body = weight of water displaced =23V×1×g=\frac{2}{3}V\times1\times g In another liquid, weight of body = 23Vg=14Vρg\frac{2}{3}Vg=\frac{1}{4}V\rho g or ρ=83gcc−1\rho=\frac{8}{3}g cc^{-1}