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Question: A body floats in a liquid contained in a beaker. The whole system as shown falls freely under gravit...

A body floats in a liquid contained in a beaker. The whole system as shown falls freely under gravity. The upthrust on the body due to the liquid is

A

Zero

B

Equal to the weight of the liquid displaced

C

Equal to the weight of the body in air

D

Equal to the weight of the immersed position of the body

Answer

Zero

Explanation

Solution

Upthrust =Vρliquid (ga)= V \rho _ { \text {liquid } } ( g - a ); where, a = downward acceleration,

V = volume of liquid displaced

But for free fall a = g

\therefore Upthrust = 0