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Question

Physics Question on Motion in a straight line

A body falls freely for 10 sec10\,sec. Its average velocity during this journey (take g=10 ms−2g = 10 \, ms^{-2})

A

100 ms−1100 \, ms^{-1}

B

10 ms−110 \, ms^{-1}

C

50 ms−150 \, ms^{-1}

D

5 ms−15 \, ms^{-1}

Answer

50 ms−150 \, ms^{-1}

Explanation

Solution

Key Idea Average velocity = Total Displacement  Time interval =\frac{\text { Total Displacement }}{\text { Time interval }}
In 10 s10 \,s, the distance covered by the body
Here,
s=12gt2s=\frac{1}{2} g t^{2}
t=10 st=10 \,s
g=10 ms−2g =10\, ms ^{-2}
∴s=12(10)×(10)2=500 m\therefore s =\frac{1}{2}(10) \times(10)^{2}=500 \,m
vav=50010=50 ms−1v_{ av }=\frac{500}{10}=50\, ms ^{-1}