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Question

Physics Question on Motion in a straight line

A body falling from a high minaret travels 40 m in the last 2 s of its fall to ground. Height of minaret is [Take g=10ms2g = 10 \,m \,s^{-2}]

A

60 m

B

45 m

C

80 m

D

50 m

Answer

45 m

Explanation

Solution

Let h be total height and t be the total time of flight. Then, h=12?10?t2=5t2(i)h = \frac{1}{2}? 10 ? t^{2} = 5t^{2}\quad\cdots\left(i\right) and h40=12?10?(t2)2=5(t2+44t)h - 40 = \frac{1}{2} ? 10 ?\left( t - 2\right)^{2} = 5\left(t^{2} + 4 - 4t\right) Using (i)\left(i\right), we get 5t240=5(t244t)5t^{2} - 40 = 5\left(t^{2} - 4 - 4t\right) or 5t240=5t2+2020t5t^{2} - 40 = 5t^{2} + 20 - 20t or 20t=6020t = 60 or t=3st = 3\, s h=5(3)2=45m\therefore\quad h = 5\left(3\right)^{2} = 45 \,m