Question

A body executing simple harmonic motion has a maximum acceleration equal to 24 m/*sec²*and maximum velocity equal to 16 meter/sec. The amplitude of simple harmonic motion is

• A. $\frac{32}{3}meters$
• B. $\frac{3}{32}meters$
• C. $\frac{1024}{9}meters$
• D. $\frac{64}{9}meters$

Answer 1

Answer: (A)

$\frac{32}{3}meters$

Answer 2

Maximum acceleration $\omega^{2}a = 24$ …..(i)

and maximum velocity $a\omega = 16$ ….(ii)

Dividing (i) by (ii) $\omega = \frac{3}{2}$

Substituting this value in equation (ii) we get

$a = 32/3meter$