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Question

Physics Question on Oscillations

A body executing SHM has its velocity 10cm/s10\, cm/s and 7cm/s7\, cm/s, when its displacements from the mean position are 3cm3\, cm and 4cm4 \,cm, respectively The length of path is :

A

10 cm

B

9.5 cm

C

4 cm

D

11.36 cm

Answer

11.36 cm

Explanation

Solution

v=ωA2x2v =\omega \sqrt{ A ^{2}- x ^{2}}
v1=10cm/secv _{1}=10\, cm / \sec
v2=7cm/secv _{2}=7\, cm / \sec
x1=3cmx _{1}=3\, cm x2=4cmx _{2}=4 cm
v1=ωA2x12v _{1}=\omega \sqrt{ A ^{2}- x _{1}^{2}}
v2=ωA2x22v _{2}=\omega \sqrt{ A ^{2}- x _{2}^{2}}
10049=A29A216\frac{100}{49}=\frac{ A ^{2}-9}{ A ^{2}-16}
A=4.76cmA =4.76\, cm
Length of the path is 2A=9.52cm2 A =9.52\, cm