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Question

Physics Question on Motion in a straight line

A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds. The velocity of the body at the end of the 7th7^{th} second is

A

10cms110 \,cm \,s^{-1}

B

20cms120 \,cm \,s^{-1}

C

5cms15 \,cm \,s^{-1}

D

30cms130 \,cm \,s^{-1}

Answer

10cms110 \,cm \,s^{-1}

Explanation

Solution

Let u and a be the initial velocity and uniform acceleration of the body. Using S=ut+12at2 S = ut + \frac{1}{2}at^{2} 200=u(2)+12a(2)2\therefore\quad 200 = u\left(2\right) + \frac{1}{2}a\left(2\right)^{2} 100=u+a...(i)100 = u + a\quad ...\left(i\right) Also 420=6u+12a(6)2420 = 6u +\frac{1}{2}a\left(6\right)^{2} 70=u+3a...(ii)70 = u + 3a \quad...\left(ii\right) Solving equations (i)\left(i\right) and (ii)\left(ii\right), we get u=115cms1,a=15cms2u = 115\, cm\, s^{-1}, a = - 15\, cm \,s^{-2} Using υ=u+at\upsilon = u + at υ=115+(15)7=10cms1\therefore\quad\upsilon = 115 + \left(-15\right)7 = 10 \,cm\, s^{-1}