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Question: A body cools from \(60^{o}C\) to \(50^{o}C\) in 10 minutes. If the room temperature is \(25^{o}C\) a...

A body cools from 60oC60^{o}C to 50oC50^{o}C in 10 minutes. If the room temperature is 25oC25^{o}C and assuming Newton's law of cooling to hold good, the temperature of the body at the end of the next 10 minutes will be

A

38.5oC38.5^{o}C

B

40oC40^{o}C

C

42.85oC42.85^{o}C

D

45oC45^{o}C

Answer

42.85oC42.85^{o}C

Explanation

Solution

605010=K(60+50225)\frac{60 - 50}{10} = K\left( \frac{60 + 50}{2} - 25 \right) …..(i)

50θ10=K[50+θ225]\frac{50 - \theta}{10} = K\left\lbrack \frac{50 + \theta}{2} - 25 \right\rbrack …..(ii)

On dividing, we get

1050θ=60θθ=42.85oC\frac{10}{50 - \theta} = \frac{60}{\theta} \Rightarrow \theta = 42.85^{o}C