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Physics Question on work, energy and power

A body, constrained to move in y-direction, is subjected to a force given by F→=(−2i^+15j^+6k^)\overrightarrow{F} = (-2\widehat{i}+15\widehat{j}+6\widehat{k})N The work done by this force in moving the body through a distance of 10j^\widehat{j} m along y-axis, is

A

150 J

B

20 J

C

190 J

D

160 J

Answer

150 J

Explanation

Solution

The correct option is(A): 150 J.

F→=(−2i^+15j^+6k^)\overrightarrow{F}=(-2\widehat{i}+15\widehat{j}+6\widehat{k})N and distance (d) = 10j^ m\widehat{j}\, m.
Work done
W=F→⋅d→=(−2i^+15j^+6k^)⋅(10j^)=150N−m=150 J\overrightarrow{F}\cdot \overrightarrow{d}= (-2\widehat{i}+15\widehat{j}+6\widehat{k})\cdot (10\widehat{j})=150 N-m =150\, J.