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Question

Physics Question on work, energy and power

A body constrained to move along y-axis is subjected to a constant force F=i^+2j^+3k^N\vec{F} = -\hat{i}+2\hat{j}+3\hat{k}\,N. The work done by this force in moving the body a distance of 4m4\, m along yy-axis is

A

4J4\,J

B

8J8\,J

C

12J12\,J

D

24J24\,J

Answer

8J8\,J

Explanation

Solution

Here, F=i^+2j^+3k^N\vec{F} = -\hat{i}+2\hat{j}+3\hat{k}\,N As the body moves a distance of 4m4\, m along yy-axis, d=4j^m\therefore \vec{d} = 4\hat{j}\,m Work done by the given force is W=Fd=(i^+2j^+3k^N)(4j^m)=8JW = \vec{F} \cdot \vec{d} = \left(-\hat{i}+2\hat{j}+3\hat{k}\,N\right)\cdot\left(4\hat{j}\,m\right)= 8\,J