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Question: A body centered cubic lattice is made up of hollow spheres of B. Spheres of solid A are present in h...

A body centered cubic lattice is made up of hollow spheres of B. Spheres of solid A are present in hollow spheres of B. Radius A is half of radius of B. What is the ratio of total volume of spheres of B unoccupied by A in a unit cell and volume of unit cell ?

A

73π64\frac{7\sqrt{3\pi}}{64}

B

73128\frac{7\sqrt{3}}{128}

C

7.π24\frac{7.\pi}{24}

D

7π643\frac{7\pi}{64\sqrt{3}}

Answer

7π643\frac{7\pi}{64\sqrt{3}}

Explanation

Solution

No. of atoms of B in unit cell = 2

Total volume of B unoccupied by A

in a unit cell = 2×43(R3r3)×π2 \times \frac{4}{3}\left( R^{3}–r^{3} \right) \times \pi = 7πR33\frac{7\pi R^{3}}{3}

vol. of unit cell = a3 = 6433R3\frac{64}{3\sqrt{3}}R^{3}

for BCC 3a\sqrt{3}a = 4R

\ rratio = 7πR3/36433R3\frac{7\pi R^{3}/3}{\frac{64}{3\sqrt{3}}R^{3}}= 7π643\frac{7\pi}{64\sqrt{3}}