Question

A body at rest splits into three parts of mass m, m and 4m respectively. The two equal masses fly off perpendicular to each other and each with speed of v. The speed of 4m will be

• A. $\frac{v}{2\sqrt{2}}$
• B. $\frac{v}{\sqrt{2}}$
• C. $\frac{v}{2}$
• D. $\sqrt{2\,v}$

Answer 1

Answer: (A)

$\frac{v}{2\sqrt{2}}$

Answer 2

From conservation of momentum $mv\sqrt{2}=4m{{v}_{1}}$ ${{v}_{1}}=\frac{v\sqrt{2}}{4}$ ${{v}_{1}}=\frac{v}{2\sqrt{2}}$