Question
Physics Question on Heat Transfer
A body at a temperature of 728∘C and has surface area 5cm2, radiates 300J of energy each minute. The emissivity is (Given Boltzmann constant =5.67×10−8Wm2K4 )
A
e =0.18
B
e=0.02
C
e=0.2
D
e=0.15
Answer
e =0.18
Explanation
Solution
a=EAt=eσ(T4−T04)At where, t= time T0= temperature of surrounding when T>T0,Q=eσT4At 300=e×(5.67×10−8)(1000)4(5.00×10−4) e=0.18