Question

A body $A$ thrown vertical upwards with a velocity v reaches a height of $200\, m$ . Another body $B$ whose mass is twice that of $A$ is thrown with a velocity $2v$ . Find the maximum height reached by $B$ .

• A. $400\, m$
• B. $800\, m$
• C. $100\, m$
• D. $200\, m$

Answer 1

Answer: (B)

$800\, m$

Answer 2

Maximum height of the particle thrown is independent of its mass and is given by
$H=\frac{v^{2}}{2\,g}$
For body A : $200=\frac{v^{2}}{2g} \dots(i)$
For body B : $H=\frac{(2v)^{2}}{2g}$
$=\frac{4 v^{2}}{2g}$
$=(4 \times 200)=800\,m$ (from (i))