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Question: A body A moves with a uniform acceleration \(a\) and zero initial velocity. Another body B, starts...

A body A moves with a uniform acceleration aa and zero initial velocity. Another body B, starts from the same point moves in the same direction with a constant velocity vv . The two bodies meet after a time t. The value of tt is

A

2va\frac { 2 v } { a }

B

va\frac { v } { a }

C

v2a\frac { v } { 2 a }

D

v2a\sqrt { \frac { v } { 2 a } }

Answer

2va\frac { 2 v } { a }

Explanation

Solution

Let they meet after time 't' . Distance covered by body A

= 12at2\frac { 1 } { 2 } a t ^ { 2 } ; Distance covered by body B = vtv t

and 12at2=vt\frac { 1 } { 2 } a t ^ { 2 } = v t

\therefore t=2vat = \frac { 2 v } { a } .