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Question: A boat travels from the south bank to the north bank of a river with a maximum speed of \(8km/h\). A...

A boat travels from the south bank to the north bank of a river with a maximum speed of 8km/h8km/h. A river current flows from west to east with a speed of 4km/h4km/h. Find the angle with which the boat should be steered to arrive at a point opposite to the point of start.
(a) 60WofN{60^\circ }W\,of\,N
(b) 30WofN{30^\circ }W\,of\,N
(c) 60SofE{60^\circ }S\,of\,E
(d) 30SofE{30^\circ }S\,of\,E

Explanation

Solution

In order to answer this question, we have to calculate the angle with which the boat should be steered to arrive at a point opposite to the point of start, we will first draw a diagram respect to the given problem and then we will take sine angle to solve for it.

Complete step by step answer:
Velocity of the boat =8km/h = 8km/h
And, the velocity of the river from west to east =4km/h = 4km/h
So, according to the question:

In the above figure, the angle is θ\theta .
So, as the angle with which the boat should be steered to arrive at a point opposite to the point of start is as:
Vbrsinθ=v sinθ=48=12  {V_{br}}\sin \theta = v \\\ \Rightarrow \sin \theta = \dfrac{4}{8} = \dfrac{1}{2} \\\
θ=30westofnorth\therefore \theta = {30^\circ }\,west\,of\,north .
Therefore, the angle with which the boat should be steered to arrive at a point opposite to the point of start is 30WofN{30^\circ }W\,of\,N .
Hence, the correct option is (b).

Note: As we know, the given question is related to the river boat topic, so to solve river boat problems, we need to understand two concepts: The speed of a boat relative to the water is equal to the speed of the boat in still water.