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Question: A boat sails 2 km east, then 4km northeast and then in an unknown direction. Final position of the b...

A boat sails 2 km east, then 4km northeast and then in an unknown direction. Final position of the boat is 5 km east from starting point. Unknown displacement is

A

2.8 km, 3°26' with north towards east

B

3km 2°26' with east

C

3.5 kin, 2°30' with south towards west

D

1.81cm, 2°36' with north towards east.

Answer

2.8 km, 3°26' with north towards east

Explanation

Solution

S\overrightarrow{S} = S\overrightarrow{S}1 + S\overrightarrow{S}2 + S\overrightarrow{S}3

5i^\widehat{i} = 2i^\widehat{i} + [(4 cos 450)i^\widehat{i} - (4 sin 45o)j^\widehat{j}] + S\overrightarrow{S}3

i.e. S\overrightarrow{S}3 = (3i^\widehat{i} - 2√2)i^\widehat{i} + 2√2j^\widehat{j}

= 0.172i^\widehat{i} + 2.828j^\widehat{j}

i.e., S3 = 0.1722+2.8282\sqrt{0.172^{2} + 2.828^{2}}

= 2.8 km

and tan θ = 0.172/2.828 = 0.0608

or θ = tan-1 0.0608

or θ = 30 26'