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Question

Physics Question on laws of motion

A boat of mass 40kg40\, kg is at rest. A dog of mass 4kg4 \,kg moves in the boat with a velocity of 10m/s10\, m/s. What is the velocity of boat?

A

4 m/s

B

2 m/s

C

8 m/s

D

1 m/s

Answer

1 m/s

Explanation

Solution

Total momentum of boat ++ dog system is conserved. From law of conservation of linear momentum, momentum of boat == momentum of dog m1v2=m2v2m_{1} v_{2}=m_{2} v_{2} m1=40kgm_1 = 40\,kg Given, v1=?,m2=4kg,v2=10m/s v_{1}=?, m_{2}=4\, kg , v_{2}=10 \,m / s 40×v1=4×10\therefore 40 \times v_{1}=4 \times 10 v1=4×1040=1m/s\Rightarrow v_{1}=\frac{4 \times 10}{40}=1\, m / s