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Question: A blue lamp mainly emits light of wavelength 45Å. The lamp is rated at 150W and 8% of the energy is ...

A blue lamp mainly emits light of wavelength 45Å. The lamp is rated at 150W and 8% of the energy is emitted as visible light. The number of Photons emitted by the lamp per second is :

A

3×10193 \times 10^{19}

B

3×10243 \times 10^{24}

C

)3×10203 \times 10^{20}

D

3×10183 \times 10^{18}

Answer

3×10193 \times 10^{19}

Explanation

Solution

: Number of photons emitted per second

=8%ofpE=8pλ100hc= \frac{8\% ofp}{E} = \frac{8p\lambda}{100hc}

=8×150×4500×10−10100×6.63×10−34×3×108= \frac{8 \times 150 \times 4500 \times 10^{- 10}}{100 \times 6.63 \times 10^{- 34} \times 3 \times 10^{8}}

=3×1019= 3 \times 10^{19}photons per second