Solveeit Logo
Login

Question

Question: A block of pure silicon at 300 K has a length ofj 10 cm and an area of \(1.0cm^{2}\) A battery of EM...

A block of pure silicon at 300 K has a length ofj 10 cm and an area of 1.0cm21.0cm^{2} A battery of EMG 2 V is connected across it. The mobility of electons is 0.14m2V−1s−10.14m^{2}V^{- 1}s^{- 1} and their number density is the electrons current is.

A

6.72×10−4A6.72 \times 10^{- 4}A

B

6.72×10−5A6.72 \times 10^{- 5}A

C

6.72×10−6A6.72 \times 10^{- 6}A

D

6.72×10−7A6.72 \times 10^{- 7}A

Answer

6.72×10−7A6.72 \times 10^{- 7}A

Explanation

Solution

: As E=Vl=2V0.1m=20Vm−1E = \frac{V}{l} = \frac{2V}{0.1m} = 20Vm^{- 1}

A=1.0cm2=1.0×10−4m2A = 1.0cm^{2} = 1.0 \times 10^{- 4}m^{2}

ve=μeE=0.14×20=2.8ms−1v_{e} = \mu_{e}E = 0.14 \times 20 = 2.8ms^{- 1}

The electron current is

}{= (1.5 \times 10^{16}) \times (1.0 \times 10^{- 4}) \times (1.6 \times 10^{- 19}) \times 2.8 }{= 6.72 \times 10^{- 7}A}$$