Question

a block of mass m slides on the wooden wedge which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is:
[ Given m= 8kg, M=16kg ]
[Assume all the surfaces shown in the figure to be frictionless]

• A. $\frac{4}{3}g$
• B. $\frac{6}{5}g$
• C. $\frac{3}{5}g$
• D. $\frac{2}{3}g$

Answer 1

Answer: (D)

$\frac{2}{3}g$

Answer 2

The correct answer is (D) : $\frac{2g}{3}$
N cos60∘ = Ma1​ = 16a1​⇒ N = 32a1​​⊥ to incline N = 8g cos30∘ − 8a1 ​sin30∘ ⇒ 32
a1​ = 4√3​g − 4a1
A2 = $\frac{\sqrt3}{9}$g
​8g sin30∘ + 8a1​ cos30∘ = ma2 ​= 8a2
a2 = g\times$$\frac{1}{2}$$\times$$\frac{\sqrt3}{9}g\times$$\frac{\sqrt3}{2}
= $\frac{2g}{3}$