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Question

Physics Question on work, energy and power

A block of mass M placed inside a box descends vertically with acceleration ‘ a ’.The block exerts a force equal to one-fourth of its weight on the floor of the box.
The value of ‘ a ’ will be

A

g4\frac{g}{4}

B

g2\frac{g}{2}

C

3g4\frac{3g}{4}

D

gg

Answer

3g4\frac{3g}{4}

Explanation

Solution

The correct answer is (C) : 3g4\frac{3g}{4}
A block of mass M placed inside a box descends vertically
By Using Newton’s 2nd law , we get
mg−mg4=mamg - \frac{mg}{4} = ma
⇒a=3g4⇒ a = \frac{3g}{4}