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Question: A block of mass 'm' is slipping down a rough inclined plane with constant speed. The force on block ...

A block of mass 'm' is slipping down a rough inclined plane with constant speed. The force on block by plane is –

A

mg

B

mg2\frac { \mathrm { mg } } { 2 }

C

Depends upon coefficient of friction

D

Depends upon angle of inclination

Answer

Depends upon angle of inclination

Explanation

Solution

Net force on block Fnet\overrightarrow { \mathrm { F } } _ { \mathrm { net } } = mg\overrightarrow { \mathrm { mg } } + FBW\overrightarrow { \mathrm { F } } _ { \mathrm { BW } }

As block is slipping with constant speed Fnet\overrightarrow { \mathrm { F } } _ { \mathrm { net } } = 0

̃ FBW\overrightarrow { \mathrm { F } } _ { \mathrm { BW } } = – mg\overrightarrow { \mathrm { mg } }

̃ FBW\mathrm { F } _ { \mathrm { BW } } = mg