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Question: A block of mass m is pulled by a constant power P placed on a rough horizontal plane. The friction c...

A block of mass m is pulled by a constant power P placed on a rough horizontal plane. The friction co-efficient between the block and the surface is m. Maximum velocity of the block will be –

A

μPmg\frac { \mu \mathrm { P } } { \mathrm { mg } }

B

μmgP\frac { \mu \mathrm { mg } } { \mathrm { P } }

C

mmgP

D

Pμmg\frac { \mathrm { P } } { \mu \mathrm { mg } }

Answer

Pμmg\frac { \mathrm { P } } { \mu \mathrm { mg } }

Explanation

Solution

P = F.v = constant

When F = mmg, net force on block becomes zero.

i.e. it has maximum or terminal velocity

\ P = (mmg)vmax

or vmax = Pμmg\frac { \mathrm { P } } { \mu \mathrm { mg } }