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Question: A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force ...

A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is –

A

PmM+m\frac { \mathrm { Pm } } { \mathrm { M } + \mathrm { m } }

B

PmM−m\frac { \mathrm { Pm } } { \mathrm { M } - \mathrm { m } }

C

P

D

PMM+m\frac { P M } { M + m }

Answer

PMM+m\frac { P M } { M + m }

Explanation

Solution

P = (M + m) a

a = P(M+m)\frac { P } { ( M + m ) }

F = Ma = PM(M+m)\frac { P M } { ( M + m ) }