Question

A block of mass m is placed on a smooth wedge of inclination θ. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

• A. mg sin θ
• B. mg
• C. $\frac{mg}{cos\theta}$
• D. mg cosθ

Answer 1

Answer: (B)

mg

Answer 2

The force exerted by the wedge on the block is equal to "mass times gravity times the sine of the angle of inclination (θ).