Question

A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration ‘a’ towards the right. The relation between a and θ for the block to remain stationary on the wedge is

• A. $a=\frac{g}{\cosec\theta}$
• B. a = g cosθ
• C. $a=\frac{g}{\sin\theta}$
• D. a = g tanθ

Answer 1

Answer: (D)

a = g tanθ

Answer 2

The correct option is (D): a = g tanθ