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Question: A block of mass m is placed at the top of a smooth wedge ABC. The wedge is rotated about an axis pas...

A block of mass m is placed at the top of a smooth wedge ABC. The wedge is rotated about an axis passing through C as shown in the figure. The minimum value of angular speed w such that the block does not slip on the wedge is-

A

(gsinθl)secθ\left( \sqrt{\frac{g\sin\theta}{\mathcal{l}}} \right)\sec\theta

B

(gl)cosθ\left( \sqrt{\frac{g}{\mathcal{l}}} \right)\cos\theta

C

(glcosθ)cosθ\left( \sqrt{\frac{g}{\mathcal{l}\cos\theta}} \right)\cos\theta

D

gsinθl\sqrt{\frac{g\sin\theta}{\mathcal{l}}}

Answer

(gsinθl)secθ\left( \sqrt{\frac{g\sin\theta}{\mathcal{l}}} \right)\sec\theta

Explanation

Solution

mw2r cos q = mg sin q

mw2l cos2 q = mg sin q

w=gsinθlcos2θ\sqrt{\frac{g\sin\theta}{\mathcal{l}\cos^{2}\theta}}=gsinθl\sqrt{\frac{g\sin\theta}{\mathcal{l}}}secq