Question

A block of mass m is placed at rest on an inclined plane of inclination q to the horizontal. If the coefficient of friction between the block and the plane is m, then the total force the inclined plane exerts on the block is-

• A. mg
• B. m mg cosq
• C. mg sin q
• D. m mg tan q

Answer 1

Answer: (A)

mg

Answer 2

mg $\sin \theta$

In static condition,

Friction, f = mgsin q, N = mg cos q

so net force through plane,

$\sqrt { ( m g \sin \theta ) ^ { 2 } + ( m g \cos \theta ) ^ { 2 } }$ = mg