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Question: A block of mass \(m\) at the end of a string is whirled round in a vertical circle of radius \(R\). ...

A block of mass mm at the end of a string is whirled round in a vertical circle of radius RR. The critical speed of the block at the top of its swing below which the string would slacken before the block reaches the top is

A

RgRg

B

(Rg)2(Rg)^{2}

C

R/gR/g

D

Rg\sqrt{Rg}

Answer

Rg\sqrt{Rg}

Explanation

Solution

At highest point mv2R=mg\frac{mv^{2}}{R} = mg

⇒ v=gRv = \sqrt{gR}